Classification of Four-Bar Linkages

Kinematics and Machine Dynamics · Chapter 3

Aykut C. Satici

Chapter overview

  • Check whether four lengths form a movable closed linkage.
  • Apply Grashof’s criterion.
  • Identify the effect of choosing a different fixed link.
  • Evaluate the transmission angle.

Can the linkage close?

A nondegenerate quadrilateral requires

\boxed{l<s+p+q.}

If l>s+p+q, the links cannot close.

If l=s+p+q, they can only lie collinearly in a degenerate assembly; this is not an ordinary moving four-bar.

Grashof’s criterion

For an assemblable four-bar:

Length test Motion class
s+l<p+q Strict Grashof
s+l=p+q Change-point case
s+l>p+q Non-Grashof

In the strict Grashof case, at least one link can rotate completely relative to an adjacent link. Rotation relative to ground depends on which link is fixed.

Crank-rocker

Crank-rocker example reproduced from the compiled notes.

The shortest link is adjacent to ground and can rotate continuously. The other ground-connected link oscillates.

The driver must be chosen consistently with the desired continuous input.

Double crank and double rocker

Double crank: ground is shortest; both ground-connected links can rotate fully.

Grashof double rocker: the coupler is shortest; both ground-connected links rock, even though the chain satisfies Grashof’s condition.

Non-Grashof: no inversion supplies a fully rotating ground-connected crank; the moving links have bounded rotation relative to ground.

Change points

s+l=p+q.

The links can pass through an all-collinear configuration. The continuation of motion can become ambiguous at this posture.

A parallelogram is a familiar example. An additional constraint or suitable drive arrangement may be needed to maintain the intended branch.

Treat equality separately from strict Grashof motion.

Worked example: classify one assembly

Let (l_0,l_1,l_2,l_3)=(100,40,120,90)\ \mathrm{mm}.

s=40,\quad l=120,\quad p=90,\quad q=100.

Closure: 120<40+90+100.

Grashof: 40+120=160<190=90+100.

The shortest link is the input, adjacent to ground: crank-rocker.

Worked example: a variable ground length

Let (l_1,l_2,l_3)=(100,200,300)\ \mathrm{mm} and let ground length be d>0.

Closure requires d<600 mm. Applying the sorted Grashof test piecewise gives

\boxed{200\leq d\leq400.}

The endpoints 200,400 mm are change-point cases.

Strict crank-rocker operation occurs for 200<d<400 mm, with the 100 mm link as crank.

Transmission angle

Let \mu be the included angle between coupler and output link, 0\leq\mu\leq\pi.

For an ideal two-force coupler exerting axial force F,

|\tau_3|=|F|l_3|\sin\mu|.

Torque transmission is strongest near 90^\circ. Near collinearity, large coupler and bearing forces produce little output torque.

Compute the angle from a triangle

Let d_A be the distance from input endpoint A to output pivot O_3.

d_A^2=l_0^2+l_1^2-2l_0l_1\cos\theta_1.

The triangle with sides l_2,l_3,d_A gives

\boxed{\cos\mu=\frac{l_2^2+l_3^2-d_A^2}{2l_2l_3}.}

A supplementary angle convention gives the same |\sin\mu| and hence the same torque magnitude.

Worked example: force transmission

For (100,40,120,90) mm and \theta_1=90^\circ:

d_A^2=11600\ \mathrm{mm^2},\qquad \cos\mu=\frac{10900}{21600}.

Thus \mu\approx59.7^\circ.

With F=500 N and l_3=0.09 m:

|\tau_3|\approx500(0.09)\sin59.7^\circ=38.9\ \mathrm{N\,m}.

Design implications

The compiled notes suggest keeping 45^\circ\leq\mu\leq135^\circ as a useful preliminary guideline.

Check the entire operating cycle, not a single configuration.

Also check branch changes, clearances, bearing forces, friction, and link strength. The angle guideline alone does not establish a safe design.

References and next chapter

Satici, Kinematics and Machine Dynamics, Chapter 3, pp. 7–9; Lecture01 classification slides, following Wilson and Sadler.

The crank-rocker figure is from the compiled notes, Fig. 3.1. Other diagrams and numerical examples are instructional additions.

Next: Chapter 4: Slider-Crank and Quick-Return Linkages.